Write the equation of a hyperbola with vertices at (1,1) and (9, 1) and foci at (0, 1) and (10, 1).

Standard form of equation for a hyperbola with horizontal transverse axis:

(x-h)^2/a^2-(y-k)^2/b^2=1, (h,k)=(x,y) coordinates of center

For given hyperbola:

x-coordinate of center=(9+1)/2=5 (use midpoint formula)

y-coordinate of center=1

center: (5,1)

length of horizontal transverse axis=8 (from 1 to 9)=2a

a=4

a^2=16

..

Foci

2c=9 ( from 1 to 10)

c=4.5

..

c^2=a^2+b^2

b^2=c^2-a^2=20.25-16=4.25

..

Equation of hyperbola:

(x-5)^2/16-(y-1)^2/4.25=1

$4

step-by-step explanation:

$30×5=$150

$150 minus $130=$20

$20÷5=$4.

hope to and hope that my answer is brainliest.(follow me )

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3