How to find the vertex of f(x)=-8x^2-8x+7

The answer to your question is: (1/2, 5)

Step-by-step explanation:

Parabola                     f(x) = 8x² - 8x + 7

                                     y = 8x² - 8x + 7

Vertical Parabola equation

( x - h)² = 4p (y - k)            Transform the original equation to this form

8x² - 8x       = y - 7            

8(x² - x  + (   )²)  = y - 7       Complete squares

8 (x² - x + (1/2)²) = y - 7 + 2    Simplification

8 (x² - x + 1/4) = y - 5

                                 (x - 1/2)² = 1/8 (y - 5)

Finally Vertex

                        (1/2 , 5)

answer is because 4×10=40

and 98×4= is 392

40,392

b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)