In triangle δabc, ∠c is a right angle and cd is the height to ab
find the angles in δcbd and δcad if:

m∠a = 20°

m∠cdb =

m∠cbd =

m∠bcd =

m∠cda =

m∠ cad=

m∠acd =

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

could you provide figure.

( - 4 , -7 )

all the lines must parallel  

step-by-step explanation:

coordinates of c = ( - 1 , 2 )

3 units left = ( -4 , 2 )

9 units down = ( - 4 , 11 )