In circle o, ac and bd are diameters. circle o is shown. line segments a c and b d are diameters. the measure of arc a b is (3 x minus 70) degrees and the measure of arc d c is (x + 10) degrees. what is marc b c? 50° 80° 100° 130°

The measurement of arc BC is 130°.

Step-by-step explanation:

Given :  circle with origin O, with two line segments AC and BD which are also diameters.

Measurement of arc AB = (3 x -70)° =

Measurement of arc DC= (x +10)° = ∠3

To find : Measurement of arc BC = ∠2 =?

Solution:

Let angle subtended by the arc AC = ∠1 = (3 x -70)°

Let angle subtended by the arc BD = ∠2

Let angle subtended by the arc DC = ∠3  = ( x + 10)°

Let angle subtended by the arc AD = ∠4

AC and BD are intersecting each other at O.

So, ∠1 = ∠3  (vertically opposite angles)..[1]

∠2 = ∠4 (vertically opposite angles)..[2]

(3 x -70)° =  (x +10)° (from [1])

3x - x = 10 + 70

∠1 = ∠3 = (x +10)° =  (40 +10)° = 50°

∠1 + ∠2 + ∠3 + ∠4 = 360°

50° + ∠2 + 50° + ∠2= 360° (from [2])

2∠2 = 360° -50° - 50°

2∠2 = 260°

∠2 = 260° ÷ 2

∠2 = 130°

The measurement of arc BC is 130°.

What is the measure of Arc E F C? The Answer is D-130

Step-by-step explanation:

Took the test on edge2020! Have a great day!

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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