Tv advertising agencies face increasing challenges in reaching audience members because viewing tv programs via digital streaming is gaining in popularity. a poll reported that 55% of 2341 american adults surveyed said they have watched digitally streamed tv programming on some type of device.

(a) calculate and interpret a confidence interval at the 99% confidence level for the proportion of all adult americans who watched streamed programming up to that point in time. (round your answers to three decimal places.) , interpret the resulting interval.

we are 99% confident that this interval does not contain the true population proportion.

we are 99% confident that this interval contains the true population proportion.

we are 99% confident that the true population proportion lies below this interval. we are 99% confident that the true population proportion lies above this interval.

(b) what sample size would be required for the width of a 99% ci to be at most 0.03 irrespective of the value of p? ? (round your answer up to the nearest integer.)

a)

The 99% confidence level for the proportion of all adult Americans who watched streamed programming up to that point in time is between (0.524, 0.576).

We are 99% confident that this interval contains the true population proportion.

b) We need a sample size of 1842.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the zscore that has a pvalue of .

The margin of error of the interval is given by:

For this problem, we have that:

99% confidence level

So , z is the value of Z that has a pvalue of , so .

The lower limit of this interval is:

The upper limit of this interval is:

The 99% confidence level for the proportion of all adult Americans who watched streamed programming up to that point in time is between (0.524, 0.576).

This means that we are 99% sure that the true population proportion is in that interval.

So the answer is:

We are 99% confident that this interval contains the true population proportion.

(b) What sample size would be required for the width of a 99% CI to be at most 0.03 irrespective of the value of p?? (Round your answer up to the nearest integer.)

We don't know the value of in this case, so we use , which is the case for which we are going to need the largest sample size.

We need a sample size of n, and n is found when M = 0.03. So

Rounding up

We need a sample size of at least 1842.

relating to or denoting a system of numbers and arithmetic based on the number ten, tenth parts, and powers of ten.

it alot will look like this 4.4

you could deduce the conclusion directly using the facts pertaining to the specific situation.

hope this .