Suppose theta is an angle in the standard position whose terminal side is in quadrant iv and cot theta= -2.
a. sv5 2.15
5 , csc o= - 5, sec @= tan
sin
=-
5
cos
v
sin
-
-
, csc e
cos
5. sec 8=1
s
covs
tana
55 25
5, cos 8- 5, csc 8-
vs
sin e_ _
sec
, tan @= --
sin 8-
din e 15
.25
, cos 8=-=-csc e-- v5, sec 8=-7tan 8=;

the answer is n

answer

you start with $5 and save $10 a week until you have at least $45wer

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v