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Mathematics, 26.09.2019 19:10 jaqui94
At 2: 00 pm a car's speedometer reads 30 mi/h. at 2: 10 pm it reads 50 mi/h. show that at some time between 2: 00 and 2: 10 the acceleration is exactly 120 mi/h2. let v(t) be the velocity of the car t hours after 2: 00 pm. then v(1/6) ā v(0) 1/6 ā 0 = . by the mean value theorem, there is a number c such that 0 < c < with v'(c) = . since v'(t) is the acceleration at time t, the acceleration c hours after 2: 00 pm is exactly 120 mi/h2.
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At 2: 00 pm a car's speedometer reads 30 mi/h. at 2: 10 pm it reads 50 mi/h. show that at some time...
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