In parallelogram abcd, m zdab = 11x + 1, m zabc = 2(7x+2), mzcdb = 6x +1, mzdca = 5x-1
find the following measures.
w
17.
18. mzdab
19. mzdcb
20. m zadc
21. m zacb
22. m zadb
in rectangle rect, ra = 7x, rc = 16.5x - 6
find the following measures
23. x
24. rc
26. ae
24. ac
25. at
26. te

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

8/k

step-by-step explanation: