(1 point) Find an equation of the tangent plane to the parametric surface x=5rcosθx=5rcos⁡θ, y=4rsinθy=4rsin⁡θ, z=rz=r at the point (52–√,42–√,2)(52,42,2) when r=2r=2, θ=π/4θ=π/4. z = Note: Your answer should be an expression of x and y; e. g. "3x - 4y"

Denote the given surface by the vector-valued function,

Then the normal vector to this plane is

When and , the normal vector is

and so the equation of the tangent plane is

Judging by the "note", you need to write the equation as , which is trivial:

s + (a + 178) = 2000

step-by-step explanation:

2000 - 178 = 1822

1822 / 2 = 911

911 + 178 = 1089

1089 + 911 = 2000

abha = 1089

shane = 911

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068