The cost of electricity in a certain city is 0.08 for each of the first 300 kwh and $0.13 for each kilowatt-hour over 300 kwh. find the number of kilowatt-hours used by a family that receives a $55.20 electric bill

The answer to your question is: The family consumed = 540 kWh

Step-by-step explanation:

Data

$ 0.08 for each of the first 300 kWh

$0.13 for each kWh over 300 kWH

Electric bill = $55.20

First, calculate if the family consume more than 300 kWh

                          300 x 0.08 = $24  that is lower than $55.2 so they consume more than 300 kWh

Calculate the difference between what they pay and the cost of 300 kWh

                             $55.20 - 24 = $ 31.2

Now, rule of three

                             1 kWh   $0.13

                             x            $31.2

           x = (31.2)(1) / 0.13 = 240 kWh

The family consumed = 300 + 240 = 540 kWh

oof cheaters cheat because they’re lazy that’s why i cheat xd

: )

step-by-step explanation:

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.