Mathematics, 14.09.2019 12:10 layja20
Show algebraically(using laws) that: ¬(p∧q)∨ p ≡ true in your answer make sure that you (1) show your steps (2) do not skip any steps and (3) justify each step with the name of the law being used.
Answers: 3
![\neg (p \wedge q) \vee p \equiv [(\neg p) \vee (\neg q)] \vee p.](/tpl/images/0231/3871/ab946.png)
![[(\neg p) \vee (\neg q)] \vee p \equiv p \vee [(\neg p) \vee (\neg q)].](/tpl/images/0231/3871/4a6ec.png)
![p \vee [(\neg p) \vee (\neg q)] \equiv [p \vee (\neg p)] \vee (\neg q).](/tpl/images/0231/3871/ce662.png)
, so that:![[p \vee (\neg p)] \vee (\neg q) \equiv \textrm{TRUE} \vee (\neg q).](/tpl/images/0231/3871/a0e36.png)
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Show algebraically(using laws) that: ¬(p∧q)∨ p ≡ true in your answer make sure that you (1) show yo...
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