Percival plans to flip a coin times and record the results of each flip. what is the probability that the coin lands with the heads side up the first times and the tails side up the last times?

P(heads on first time ) =  

P(tails on last flip) =  

Step-by-step explanation:

when Percival flips coin several times and record the result.

so every time he tosses coin there is probability of getting heads or tails is

P(heads) =  

and for tails

P(tails) =  

so, probability of getting heads while tossing coin first time is  equal to

               P(heads on first time ) =  

again, probability of getting tails while tossing coin for last time is  equal to

               P(tails on last flip) =  

it would not be increasing by nothing that i can see probably by 25 percent that is all i can sat\y for now if i have any thing else to say i will edit this.

step-by-step explanation:

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0