Agroup of friends decided to divide the $800 cost of a trip equally among themselves. when two of the friends decided not to go on the trip, those remaining still divided the $800, 800 cost equally, but each friend’s share of the cost increased by $20. how many friends were in the group originally?

The number of friends were in the group originally is 10.

Step-by-step explanation:

Given : A group of friends decided to divide the $800 cost of a trip equally among themselves. When two of the friends decided not to go on the trip, those remaining still divided the $800, 800 cost equally, but each friend’s share of the cost increased by $20.

To find : How many friends were in the group originally?

Solution :

Let the number of friends be 'x'.

A group of friends decided to divide the $800 cost of a trip equally among themselves.

i.e. Cost of trip for each friend is

When two of the friends decided not to go on the trip, those remaining still divided the $800.

i.e. Cost of trip for each friend is  

The increase in cost for each remaining friend is $20.

i.e.  

Divide the equation by 20,

Taking LCM,

Cross multiply,

Solving by middle term split,

Rejecting x=-8.

Accepting x=10.

Therefore, The number of friends were in the group originally is 10.

answer: it is 8

step-by-step explanation:

you know why its 8

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step-by-step explanation:

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