A mean score of driving exam for a group of drivers education students 72 points with a standard deviation of 5 points. Apply Chebychev's theorem to the data using K=2

At least the 75% of the scores of driving exams are between 62 and 82 points.

Step-by-step explanation:

The chebyshev theorem said that the proportion of any distribution that is less than k deviations of the mean is at least .

So, if we replace k by 2, we can calculated the limits as:

Where x is the mean and s is the standard deviation.

Then,   is equal to:

It means that at least the 75% of the scores of driving exams are between 62 and 82 points.

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)

idk this answer sorry cant on this one.

step-by-step explanation: