Consider some 4-sided dice. roll two of these dice. let x be the minimum of the two values that appear. let y denote the maximum. let a j be the event containing all outcomes in which the minimum of the two dice is j or greater. let x j indicate whether a j occurs. then x = x 1 + x 2 + x 3 + x 4 .

Best answer that i found on yahoo ok   set :   x= length of 2nd piece in cm  x- 3= length of 1st piece in cm  x-4= length of 3rd piece in cm  then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20  3x - 7= 20  3x= 27  x= 9  the shortest piece is the third piece which is x- 4  x-4  9-4 = 5  the length of the smallest piece is 5 cm.  the other lengths are  9 cm  6 cm

Dang i wish i could , good luck (i’m bad at math)

1/6 of a chance i would believe