Question
enrique is making a party mix that contains raisins and nuts. for each ounce of nuts, he uses twice the amount of raisins.
how many ounces of nuts and how many ounces of raisins does he need to make 24 ounces of party mix?

He needs 16 ounces of raisins and 8 ounces of nuts

Step-by-step explanation:

Let

x > the number of ounces of raisins

y > the number of ounces of nuts

we know that

x+y=24 > equation A

x=2y > equation B

Solve the system by substitution

Substitute equation B in equation A and solve for y

(2y)+y=24

3y=24

y=8 ounces of nuts

Find the value of x

x=2(8)=16 ounces of raisins

therefore

He needs 16 ounces of raisins and 8 ounces of nuts

8 ounces of nuts and 16 ounces of raisins.

Step-by-step explanation:

Enrique is making a party mix that contains raisins and nuts.

For each ounce of nuts, he uses twice the amount of raisins.

Let the amount of nuts = x

the amount of raisins = 2x

Total amount of party mix he need to make = 24 ounces

the equation will be

x + 2x = 24

3x = 24

x =

x = 8 ounces

The amount of raisins = 2x = 2(8)

                                    =  16 ounces

For 24 ounces of party mix Enrique need  8 ounce of nuts and 16 ounces of raisins.

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

i have no idea just need points sorry

step-by-step explanation: