Consider the following reaction: 2nobr(g) 2no(g) + br2(g)if 0.412 moles of nobr(g), 0.678 moles of no, and 0.224 moles of br2 are at equilibrium in a 10.3 l container at 516 k, the value of the equilibrium constant, kc, is:

Explanation: The given chemical reaction is:

Equilibrium constant (Kc) in general is written as:

Note:- Coefficients are written as their powers

So, the Kc expression for the above reaction will be:

Equilibrium moles are given for all of them. Let's divide the moles by given liters to get the concentrations.

  = 0.040 M

  = 0.0658 M

  = 0.0217 M

Plug in the values in the equilibrium expression to calculate Kc.

law of conservation of matter

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