Prove the segments joining the midpoint of consecutive
sides of an isosceles trapezoid form a rhombus.
use the distance formula to find de ef fg and gd

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

using pemdas, (order of operations) you'll see the answer is 24.

10 - 8 = -2

  8 - 6 = -2

etc, so -2 is the common difference

step-by-step explanation: