Harley graphs a polygon that is located entirely inside quadrant i. he rotates the figure clockwise 90° about the origin and then
reflects the rotated figure over the x-axis. he translates the resulting figure 3 units to the left and 3 units up. which best describes
the location of the final image?
quadranti
quadrant ii
above the x-axis
left of the y-axis

Above the x-axis

Step-by-step explanation:

Lets assume a polygon that has coordinates at A(3,2), B(3,4),C(6,4),D(6,2).

This polygon is in the 1st quadrant

so rotate it clockwise 90° about the origin, you apply the rule that point of object (h,k) will change to (k,-h) hence

A (3,2) ⇒A'(2,-3)

B (3,4) ⇒ B'(4,-3)

C (6,4) ⇒C' (4,-6)

D (6,2) ⇒D' (2,-6)

the image is in the 4th quadrant

Reflecting the rotated figure on the x-axis we get

A''=(2,3)

B''=(4,3)

C''=(4,6)

D''=(2,6)

it is on the 1st quadrant

The translation is(-3,3)

The image will be

A'''=(-3+2,3+3) = (-1,6)

B'''=(-3+4,3+3)= (1,6)

C'''=(-3+4,6+3)= (1,9)

D'''=(-3+2,6+3)= (-1,9)

the final figure above x-axis

you answer is a

step-by-step explanation: