Amass weighing 13 lb stretches a spring 4.5 in. the mass is also attached to a damper with coefficient y. determine the value of y for which the system is critically damped. assume that g = 32 ft/s^2.

55.227

Step-by-step explanation:

Given data

mass =13lb

spring stretches by =4.5in=0.375 ft

g=

Now Spring constant K

mg=kx

k=

For critical damping

and

substituting values

c=55.227 lb.sec/ft

36/60

36/2=18

60/2=30

18/30

18/3=6

30/3=10

6/10

6/2=3

10/2=5

your final answer would be 3/5 of an

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step-by-step explanation: