Solve the following nonhomogeneous systems:
y'1 = 4y1 - 2y2 - 2x - 5, y1(0) = 2
y'2 = 3y1 - y2 - 2x - 3, y2(0) = 2

-6 is the correct option from the above given options

where is abdul's work? don't see that anywhere posted : /

step-by-step explanation:

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.