Write a polynomial function of least degree with integral coefficients that has the given zeros. –2, –3,3 – 6i

f(x) = (x+2)(x+3)(x-(3-6i))(x-(3+6i))

f(x) = 270 + 189 x + 21 x^2 - x^3 + x^4

Step-by-step explanation:

First of all, we must know that complex roots come in conjugate pairs.

So the zeros of your equation would be

x = -2

x = -3

x = 3 - 6i

x = 3 + 6i

Your polynomial is of fourth degree.

f(x) = (x-(-2))(x-(-3))(x-(3-6i))(x-(3+6i))

f(x) = (x+2)(x+3)(x-(3-6i))(x-(3+6i))

Please , see attached image below for full expression

f(x) = 270 + 189 x + 21 x^2 - x^3 + x^4

The required polynomial is .

Step-by-step explanation:

The general form of a polynomial is

where, a is a constant, are zeroes with multiplicity respectively.

It is given that  –2, –3,3 – 6i are three zeroes of a polynomial.

According to complex conjugate root theorem, if a+ib is a zero of a polynomial, then a-ib is also the zero of that polynomial.

3 – 6i is a zero. By using complex conjugate root theorem 3+6i is also a zero.

The required polynomial is

On further simplification, we get

Therefore the required polynomial is .

78.59 is the mean

step-by-step explanation:

x=-7

step-by-step explanation:

x+3=-10

-10+3=-7

x=-7