How could you use descartes' rule and the fundamental theorem of algebra to predict the number of complex roots to a polynomial, as well as find the number of possible positive and negative real roots to a polynomial?

Descartes' rule states that the possible number of the positive roots of a polynomial is equal to the number of sign changes in the coefficients of the terms or less than the sign changes by a multiple of 2.

The Fundamental Theorem of Algebra states that every polynomial equation over the field of complex numbers of degree higher than 1 has a complex solution, furthermore any polynomial of degree n has n roots.  

Remember that the complex numbers include the real numbers.

Suppose we are given the polynomial x^3+3x^2-x-x^4-2, we arrange the terms of the polynomial in the descending order of exponents:

-x^4+x^3+3x^2-x-2, count the number of sign changes, there are 2 sign changes in the polynomial, so the possible number of positive roots of the polynomial is 2 or 0.

returning to our polynomial above, -x^4+x^3+3x^2-x-2, it has degree 4 and so has n roots. Note that complex roots always come in pairs, so here is what can be said from these two rules:  

degree 1 has 1 real root

degree 2 has 2 real roots or 2 complex roots

degree 3 has 3 real roots or 1 real root and 2 complex roots

degree 4 has 4 real roots or 2 real roots and 2 complex roots  

note that if the degree is odd, there will be at least 1 real root

Step-by-step explanation:

its c or d   take a lucky guess my dude

8

step-by-step explanation:

just put √(2) * √(32) into a calculator. that will make the answer be 8.