Un rombo tienen un angulo de 22 grados. cuanto vale la suma de sus angulos que no midan 22

The answer is:

The sum the other angles that do not measure 22° is equal to 316°.

To find the sum of the rest of the angles, we need to  remember that a rhombus has two adjacent and equal angles, and also it has two opposite and equal angles.

So, we are given that the rhombus has an angle of 22°, and to calculate the other angles, let be the given angle an adjacent angle, so:

Hence, we have that the sum of its other angles that do not measure 22° is equal to 316°.

Have a nice day!

answer: 19 is   2

step-by-step explanation: i just looked at your answer and wrote it down

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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