Consider the rectangle in the first quaurant with its lower left vertex at the origin and upper right vertex at the point P. The x-coordinate of point P is increasing at a constant rate of 7
units per second, and the y-coordinate of point P is decreasing at a constant rate of 6 units
per second. At the instant when point P is at x = 3 and y = 4, what is the rate at which
the area of the rectangle is changed, in square units per second?

False is the answer i just took a quiz

You this is right

The answer is false

You need to figure out at which x-value does the graph has a tangent line slope of -1.remember, the derivative is the slope of the tangent line. so find the derivative function and set it to equal -1 to find the x-value that will have a tangent line slope of 0.differentiate with the chain rule.    set the derivative to equal -1 and solve for x.      take log base 10 of both sides. also recall that  .    so the x-coord of the point of tangency is .the y-coordinate of this point of tangency can be calculated using the original function:     using point-slope form, the equation of the tangent line is      the x-intercept of this tangent line is when the graph is at y=0.    this rounds off to  .choice c.