At a competition with 7 runners, medals are awarded for first, second, and third places. each of the 3 medals is different. how many ways are there to award the medals? decide if this is a permutation or a combination, and find the number of ways to award the medals. o a. permutation; number of ways = 210 o b. combination; number of ways = 210 o c. permutation; number of ways = 35 o d. combination; number of ways = 35

Option A - Permutation; number of ways = 210

Step-by-step explanation:

Given : At a competition with 7 runners, medals are awarded for first, second, and  third places. Each of the 3 medals is different.

To find : How many ways are there to  award the medals?        

Solution :

There are 7 runners but medals are three.

The first runner up got first medal as one is locked.

The second runner up got second medal as second is locked.

The third runner up got the third medal.

So, There is a permutation.

Number of ways to award the medals is

We know,

Substitute the values,

Therefore, Option A is correct.

Permutation; number of ways = 210

answer: hey there,

the answer you are looking for is a..

hope this you!

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation: