Plz plz me friends in addition to the facts in the diagram, which other statements are necessary to prove that ∆abc is congruent to ∆efg by the asa criterion? i. m∠b = m∠f ii. bc = fg iii. m∠a = m∠e iv. fg = 3 v. m∠b = m∠e a. i only b. iii or v only c. i and iii only d. i or iv only

The answer is i and iii only ⇒ answer C

Step-by-step explanation:

* Lets revise the cases of congruence

- SSS  ⇒ 3 sides in the 1st Δ ≡ 3 sides in the 2nd Δ  

- SAS ⇒ 2 sides and including angle in the 1st Δ ≡ 2 sides and  

 including angle in the 2nd Δ

- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ

 ≡ 2 angles and the side whose joining them in the 2nd Δ

- AAS ⇒ 2 angles and one side in the first triangle ≡ 2 angles

 and one side in the 2ndΔ

- HL ⇒ hypotenuse leg of the first right angle triangle ≡ hypotenuse

 leg of the 2nd right angle Δ

* Lets solve the problem

- From the figure in Δ ABC and Δ EFG

∵ AB = 2 units

∵ ∠A and ∠B are the end vertex of AB

∵ EF = 2 units

∵∠E and ∠F are the end vertex of EF

∴ Δ ABC is congruent to Δ EFG if:

# m∠B = m∠F

# m∠A = m∠E

∴ The necessary statements to prove that Δ ABC is congruent to

   Δ EFG by ASA are:

   i. m∠B= m∠F

   iii. m∠A = m∠E

* The answer is i and iii only

what do u need to know

step-by-step explanation:

b. y = 4x - 2

step-by-step explanation:

to find a parallel equation to an equation, make sure both equations have the same slope but different y-intercepts.

y = 4x + 1

4 = slope

1 = y-intercept

y = 4x - 2

4 = slope

-2 = y-intercept

they both have the same slope but different y-intercepts, so, b. is the correct answer.

and to check your work, you can graph both equations. : )