Atoy american eskimo dog has a mean weight of 8 pounds with a standard deviation of 1 pound. assuming the weights of toy eskimo dogs are normally distributed, what range of weights would 95% of the dogs have? a. 7-9 poundsb. 6-10 poundsc. 5-11 poundsd. 4-12 pounds

Option b) 6-10 lbs

Step-by-step explanation:

Given that X, the weight of  toy American Eskimo dog has mean of 8 pounds with a standard deviation of 1 pound

For 95% of the dogs according to normal distribution would lie between 2 std deviations on either side of the mean.

i.e. lower bound= Mean- 2 std deviation = 8-2 =6

Upper bound = Mean +2 std dev = 8+2 =10

Hence range of weights would be

6-10 lbs

Option b is the answer

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

if i put something wrong your not gonna like it so rather not say nothing.