![3\log_4x=\log_432+\log_42\qquad\text{use}\ \log_ab^c=c\log_ab\ \text{and}\ \log_ab+\log_ac=\log_a(bc)\\\\\log_4x^3=\log_4(32\cdot2)\\\\\log_4x^3=\log_464\iff x^3=64\to x=\sqrt[3]{64}\\\\x=4](/tpl/images/0307/2056/553f0.png)
What is the solution to the equation below?
3log4x=log432+log42
x=-8
x=-4
x...
Mathematics, 10.10.2019 15:30 zacklofton6518
What is the solution to the equation below?
3log4x=log432+log42
x=-8
x=-4
x=4
x=8
Answers: 2
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