Which of the binomials below is a factor of this trinomial? x2 + 6x + 8

(x+4)(x+2)

Step-by-step explanation:

Distributive property of 2 binomials:

First, outer, inner, last

(a+b)(c+d) = ac+ad+bc +bd

Factor x^2 into x*x

Factor 8 into 2*2*2

Find what two numbers add up to 6 and multiply to get 8

1 and 8 do not work because they add up to 9.  2 and 4 work because they add up to 6.  

Check: (x+4)(x+2)

First:  x*x = x^2

Outer: 2*x

Inner: 4*x

Last: 2*4 = 8

Add together: x^2+2x+4x+8 = x^2+6x+8

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation: