Is (0,0) a solution to this system?

The correct answer is option D

No. (0, 0) satisfy y ≥ x² + 2x -4 but does not satisfy y > x² + 2x + 1

Step-by-step explanation:

It is given two inequalities

y ≥ x² + 2x -4

y > x² + 2x + 1

Check (0, 0) satisfy the inequalities

1).  y ≥ x² + 2x -4

0 ≥ 0² + 2*0 -4

0 ≥  -4

It is true

2). y > x² + 2x + 1

0 > 0² + 2*0 + 1

0  > 1

It is not true

The correct answer is option D

No. (0, 0) satisfy y ≥ x² + 2x -4 but does not satisfy y > x² + 2x + 1

32/80  

91/140

the last one 54 doesn't go into 45. 54/100 ?

step-by-step explanation:

answer

d. 10

explanation

the distance from point y to wx is the height of the triangle.

using pythagoras theorem,

group similar terms to get,

this implies that,

take positive square root of both sides to get,

this implies that,