What is the precipitate in the following reaction?
2AgNO3(aq) + Na2S(aq) → Ag2S(s) + 2NaNO3(aq)

2Ag(+1)(aq) + S(-2)(aq) --> Ag2(+1)S(-2)(aq)

Explanation:

The final equation is

2Ag(+1)(aq) + S(-2)(aq) --> Ag2(+1)S(-2)(aq)

2Ag(+1)NO3(-1)(aq) + Na2(+1)S(-2)(aq) --> Ag2(+1)S(-2)(s) + 2Na(+1)NO3(-1)(aq)

AgNO3, Na2S, and NaNO3 are all strong electrolytes, so we immediately separate those, making the new equation:

2Ag(+1)(aq) + 2NO3(-1)(aq) + 2Na(+1)(aq) + S(-2)(aq) --> Ag2(+1)S(-2)(s) + 2Na(+1)(aq) + 2NO3(-1)(aq)

After that, you cancel out all the ions that appear more than once, which in this case would leave us with a final equation of...

2Ag(+1)(aq) + S(-2)(aq) --> Ag2(+1)S(-2)(aq)

the right answer is c i just did the question.