Jorge needs to reflect a figure across the line y= -4 which statements are correct regarding steps he could take to complete the reflection? check all that apply. jorge should graph in the vertical line with values of –4 for the line of reflection. jorge could count how far each pre-image point is from the line of reflection along the perpendicular from the point to the line of reflection. jorge could count how far each vertex of the figure is from the y-axis and count the same distance on the other side. jorge will not move any point that lies on the line of reflection. jorge could check his work by seeing if each segment joining a pre-image point with its image has the midpoint on the line of reflection. jorge could check his work by making sure that the image has the same orientation as the original.

see below. × signifies a wrong choice; → signifies a correct one

Step-by-step explanation:

× Jorge should graph in the vertical line with values of –4 for the line of reflection. (The line of reflection is horizontal.)

→ Jorge could count how far each pre-image point is from the line of reflection along the perpendicular from the point to the line of reflection.

× Jorge could count how far each vertex of the figure is from the y-axis and count the same distance on the other side. (He could do this pointless exercise, but it has no relation to the problem. The y-axis (x=0) is not the line of reflection.)

→ Jorge will not move any point that lies on the line of reflection. (All points on the line of reflection are reflected to themselves.)

→ Jorge could check his work by seeing if each segment joining a pre-image point with its image has the midpoint on the line of reflection. (This is what is meant by "line of reflection.")

× Jorge could check his work by making sure that the image has the same orientation as the original. (A reflected image as an orientation opposite that of the original, a fact you see every time you look in a mirror.)

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl