The distance of one lap around a school track is \frac{1}{4} mile. sherrie walks 5 laps around the track. how many more laps must sherrie walk to reach a total distance of 3.5 miles?

Sherrie must walk 9 more laps.

Step-by-step explanation:

You know that one lap around the school track is or 0.25 miles.

Let be the distance in miles that Sherrie walks in 5 laps.

To calculate     you need to multiply 0.25 miles by 5. Then:

Let be   the distance left that Sherrie must walk to reach a total distance of 3.5 miles.

To calculate    you need to subtract 3.5 miles and 1.25 miles. Then:

Let be the number of more laps that  she must walk to reach a total distance of 3.5 miles.

If she needs to walk 2.25 miles more to reach a total distance of 3.5 miles and 1 lap is 0.25 miles, then "x" is:

She must walk 9 more laps.

a. positive: 2 or 0; negative : 2 or 0; complex: 4or2or0

the linear relationship that represents a variation in direct proportion is the linear function that varies according to the numbers of its domain, for example the cost of producing x number of items can be represented in direct proportion by f (x) = mx + b, where m is the constant of proportionality, x the number of articles produced and b the fixed cost