Find the center and radius of circle and graph it

centre = (0,5/2)

radius = 3/2

Step-by-step explanation:

The centre-radius form of the circle equation is in the format

(x – h)² + (y – k)² = r²,

with the centre being at the point (h, k) and the radius being "r"

Given in the question an expression which can be write as

(x – 0)² + (y – (5/2))² = (3/2)²

So, by translating we can say that

centre = (0,5/2)

and

radius = 3/2

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12