Given: abcd is a trapezoid, ab = 13,cd = 14, bc = 5, and ad = 20. find: aabcd

140

Step-by-step explanation:

Consider trapezoid ABCD. Draw two heights BE and CF. Quadrilateral BEFC is a rectangle, then EF = BC = 5 and BE = CF = y.

Let AE = x, then FD = AD - AE - EF = 20 - x - 5 = 15 - x.

Triangles ABE and CDF are two right triangles. By the Pythagorean theorem,

Thus,

Subtract from the second equation the first one:

Therefore,

The area of the trapezoid is

∠cbe and ∠deb are same-side interior angles.

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