The sum of four consecutive even integers is at least 244. find the least possible value of the first integer.

x + x +1 + x +2 + x + 3 >= 244

=》 4x + 6 >= 244

=》 4x >= 238

=》 x >= 238/4 >= 59.5

since x is an integer...least value of x is 60

The least possible even integer is 58

Let's let x be an even integer. The next three would be shown by x+2, x+4 x+6 so now we can add all these to equal 244. Shown with an equation would look like:

x + x+2 + x+4 + x+6 = 244

Combine like terms will be:

4x+12=244

Subtract 12 from both sides we will get

4x=232

Now Divide each side by 4

x=58

So now put x in the above equation and we get  the numbers

x=58,

x+2= 60

X+4 =62

x+6= 64

The least one is 58

umumumumum

im not sure