Arocket launched vertically from the ground with an initial veocity of 56ft? sec (a) write a quadratic function that shows the height, in feet, of the rocket t seconds after it was launched.
(b)graph h(t) on the coordinate plane.
(c) use your graph from part 3(b) to determine the rocket’s maximum height, the amount of time it took to reach its maximum height, and the amount of time it was in the air.

pl

Step-by-step explanation:

Ballistic motion is usually modeled by the quadratic ...

  h(t) = -1/2g·t^2 +v0·t +h0

where g is the acceleration due to gravity, v0 is the initial upward velocity, and h0 is the initial height. Here, we have g = 32 ft/s^2, v0 = 56 ft/s, h0 = 0.

(A) That makes our quadratic function be ...

  h(t) = -16t^2 +56t

(B) see the attachment for a graph

(C) see the attachment for the time and height at the highest point.

step-by-step explanation:

i found the koficent of the linear function and i foun c acordind to the strict formula y=kx+c and then i took 2 as an x and replacet it on the formula i found and then foun the y

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4