Can you me
i need on 5 and 6

5) first find the gradient using the formula:

y2-y1/x2-x1 (you have to use 2 sets of coordinates on the line)

im using the coordinates (20,40) and (35,50)

50-40/35-20

=10/15

gradient = 2/3

y=2/3x+c

subsitute a set of coordinates

im using (20,40)

40 = 2/3 (20) + c -> (c is the y intercept)

40 = 40/3 + c

c = 40-40/3

c = 80/3

y = 2/3x + 80/3

6) repeat

find the gradient, im using the points (40,20) and (30,50)

50-20/30-40

30/-10

gradient = -3

to find the y intercept, subsitute a pair of coordinates into

y = -3x + c

im using the coordinates (40,20)

20 = -3(40) + c

20 = c - 120

c = 20 + 120

c = 140

y = -3x + 140

1,918

step-by-step explanation:

just take the area of the square and then the area of the circle then subtract the circle area from the squares area

step-by-step explanation: