Factor the polynomial.
x2 + x - 6

a)
(x - 6)(x +1)

b)
(x - 2)(x + 3)

c)
(x + 2)(x - 3)

d)
(x + 6)(x - 1)

x2 + x - 6

A)  (x - 6)(x +1)  

B)  (x - 2)(x + 3)  

C)  (x + 2)(x - 3)  

D)  (x + 6)(x - 1)

Step-by-step explanation:

(x-2)(x+3)=x^2+3x-2x-6=x^2+x-6

(3x-8) or (3x+8)

step-by-step explanation:

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true