Fvaries jointly as g, h, and j. one set of values is f = 18, g = 4, h=3, j=5. find f when g= 5, h=12,and j=3

f = 27

Step-by-step explanation:

F varies jointly as g, h, and j

f = k* ghj

We know f = 18, g = 4, h=3, j=5.

Substituting these in

18 = k* 4*3*5

18 = k* 60

Divide each side by 60

18/60 = k*60/60

3/20 = k

f = 3/20 *ghj

Now we need to find f when g= 5, h=12,and j=3

f = 3/20 * 5*12*3

f = 27

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐