Part 1. this is the graph of y=1/2x+10. use the graph to show that equal intervals of x-values have equal differences of y-values. part a of part 1. table # 1 y=-1/2(6)+10= table #2 y=-1/2(10)+10= difference =__ difference =__ part b of part 1 difference in x-values for each interval is difference =(p+k)= part c of part 1 the difference in the y-values for each interval is part d of part 1 does your answer in part c depend on p? if not what does it depend on?

A. y = 7 and y = 5, Difference is 4 and -2 respectively

B. Difference is 4 and (p+k)-p = k

C. Difference is -2

D. Answer in part C does not depend on 'p' but it depends on 'k'.

Step-by-step explanation:

We have .

Part A. Now, the values of y are:

Table 1: i.e. i.e. y = 7

Table 2: i.e. i.e. y = 5

Thus, in Table 2, the difference in x-axis = 14-10 = 4 and the difference in y-axis = 3-5 = -2.

Part B. The difference in x-values for each interval is 4.

The value is constant because = (p+k)-p = p+k-p = k.

Part C. The difference in x-values for each interval is -2.

Part D. As, the difference for y-values is .

So, we get that the answer in part C does not depend on 'p' but it depends on the value of 'k'.

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)