Cody has $700 in a savings account that pays 4% simple interest what is the amount of money cody will have in his back account after 2 years if he leaves his money in the bank

I₂ = 757.12$ (after two years)

Step-by-step explanation:

When the realized interest is added to the basic investment at the end of each year, we use the following formula:

I₂ = I ( 1 + (r/100))²  for two years

I₂ = 700 ( 1 + (4/100))² = 700 · 1.04² = 700 · 1.0816 = 757.12$

I₂ = 757.12$

God with you!!!

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b