Find the vertex of the parabola y=x^2 — 2x + 3/10

The vertex would be (1, -7/10)

Step-by-step explanation:

In order to find the vertex, start by finding the x-coordinate. The x-coordinate can be calculated using -b/2a, in which a is the coefficient of x^2 and b is the coefficient of x.

-b/2a

-(-2)/2(1)

2/2

1

Now that we know the value of the x-coordinate as 1, we can use it in the equation to find y.

y = x^2 - 2x + 3/10

y = (1)^2 - 2(1) + 3/10

y = 1 - 2 + 3/10

y = -7/10

8

step-by-step explanation:

this is a subtraction problem.

10 - 2 = 8

what are you trying to solve here

step-by-step explanation: