If p(x)=2x^2-4 and q(x)=x-3, what is (poq)(x)

2x^2 -12x+14

Step-by-step explanation:

(poq)(x)=

p(q(x))

Substitute q(x) in for x in the function p(x)

p(x)=2x^2-4

p(q(x)) = 2* q(x)^2-4

           = 2(x-3)^2 -4

FOIL

          = 2( (x-3) (x-3) -4

          =2( x^2 -3x-3x+9)  -4

         =2 (x^2 -6x+9) -4

Distribute

            =2x^2 -12x +18 -4

 Combine like terms

            =2x^2 -12x+14

is there answer choices?

europa2433

europa2433

step-by-step explanation: