30 pts + brainliest for right/best !

Solve for X in the 2nd equation:

x+2z = 0

Subtract 2z from both sides:

x = -2z

Replace x in the first equation with -2z

-2z +y -z = 1

Combine like terms:

-3z +y = 1

Add 3z to both sides:

y = 3z +1

Replace x and y in the 3rd equation:

2(-2z) + 2(3z+1) = 4

-4z + 6z + 2 = 4

2z +2 = 4

2z = 2

z = 1

Now replace z with 1 in the other equations for x and y:

x = -2z = -2(1) = -2

y = 3z +1 = 3(1) +1 = 3+1 = 4

So you have x = -2, y = 4 ans z = 1

The answer would be written as (-2,4,1)

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b