Suppose given △abc with a line segment de connecting sides ab and bc so that de ∥ ac . the lengths of the sides of △dbe are three times shorter than the lengths of the sides of △abc. what is the area of trapezoid adec if the area of △abc is 27 cm^2?

24 cm^2

Step-by-step explanation:

See the attached diagram

ABC is a triangle, D, E are points on AB and BC.  DE is parallel to BC>

Also DBE has sides 1/3 times that of ABC

We have triangles ABC and DBE are similar with proportionality of sides as 1:3

Hence area of triangle DBE = 1/9 times area of ABC = 3 sq cm.

Area of trapezium ADEC = Area of triangle ABC - area of triangle DBE

=27-3 = 24 cm^2

Answer is 24 cm^2

if im not mistaking its

step-by-step explanation: