Find an equation for the line that passes through the points , −3−3 and , 5−1 .

y +3 = (1/4)(x +3)

The two-point form of the equation for a line is good for this.

... y -y1 = (y2-y1)/(x2-x1)(x -x1)

Substituting your values, we have ...

... y -(-3) = (-1-(-3))/(5-(-3))(x -(-3))

... y +3 = 2/8(x +3)

Since you ask for "an equation," we can leave it in this form.

... y +3 = (1/4)(x +3)

Or we can rearrange it to slope-intercept form:

... y = (1/4)x -(2 1/4)

or put it in standard form:

... x -4y = 9

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

answer: plz give a pic and answer choices so i can answer!

step-by-step explanation: