How would the expression x3 - 64 be rewritten using difference of cubes? a. (x + 4)(x2 - 4x - 16) b. (x - 4)(x2 + 4x + 16) c. (x + 4)(x2 - 4x + 16) d. (x - 4)(x2 + 16x + 4)

B.(x - 4)(x2 + 4x + 16)

Step-by-step explanation:

Difference of cubes can be rewritten as:

a^3 – b^3 = (a – b)(a^2 + ab + b^2)

So in this case, x^3 - 64 = x^3 - (4)^3 where a = x and b = 4

= (x-4)(x^2 + 4x + 4^2)

= (x-4)(x^2 + 4x + 16)

The answer is B.

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step-by-step explanation:

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