In parallelogram abcd , diagonals ac¯¯¯¯¯ and bd¯¯¯¯¯ intersect at point e, ae=x2−16 , and ce=6x . what is ac ? enter your answer in the box.

Step-by-step explanation:

Given ABCD is a parallelogram.

And diagonals AC and BD intersects at point E.

Note: Diagonals of a parallelogram intersects at mid-point.

E is the mid point of diagonal AC

Therefore,

AE = CE.

Plugging expression for AE and CE, we get

Subtracting 6x from both sides, we get

Factoring quadratic

(x+2)(x-8) =0.

x+2 =0  => x=-2.

x-8=0  => x=8.

We can't take the length by a negative number. Therefore, x=8.

Now, plugging x= 8 in CE =6x, we get

CE = 6(8) = 48.

We need to find the length of AC.

AC would be two times of CE.

Therefore, AC = 2 × 48 = 96.

idk i would have to be there to under stand it

step-by-step explanation:

idk i would have to be there to under stand it

sine

step-by-step explanation: